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15x^2-49x+26=0
a = 15; b = -49; c = +26;
Δ = b2-4ac
Δ = -492-4·15·26
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-29}{2*15}=\frac{20}{30} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+29}{2*15}=\frac{78}{30} =2+3/5 $
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